A body of mass M is kept on a rough horizontal surface (friction coefficient = μ). A person is trying to pull the body by applying a horizontal force but the body is not moving. The force by the surface on A is F, where

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KollegeApply · Accepted Answer

Mg $\leq$ F $\leq$ Mga sqrt(1+mu^2) Let T be the force applied on an object of mass M. If T = 0, Fmin = Mg. If T is acting in the horizontal direction, then the body is not moving. $\therefore$ T = μ(mg) Fmax = sqrt("Mg"^2+"T"^2) = sqrt("Mg"^2+(mu"Mg")^2) Thus, we have: Mg $\leq$ F $\leq$ Mga sqrt(1+mu^2)

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