A charge Q is placed at the centre of a cube. The electric flux through one of its faces is ______.

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A charge Q is placed at the centre of a cube. The electric flux through one of its faces is underlinebb(Q/(6epsi_0)). Explanation: Assuming the cube as a Gaussian surface, the total flux passing through the cube of side l can be given as, phi = Q/epsi_0 Flux through each face of the cube: As the charge is placed symmetrically to each face of the cube, thus electric flux passing through each face is equal. $\therefore$ Electric flux passing through each face, phi^' = phi/6 = Q/(6epsi_0)

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