A chord of a circle of radius 10 cm subtends a right angle at the centre. The area of the minor segments (given, $\pi$ = 3.14) is

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KollegeApply · Accepted Answer

Area of minor segment = Area of sector AOBC - Area of right traingle AOB `= 90^circ/360^circpi("OA")^2-$\frac{1}{2}$xx"OA"xx"OB" =$\frac{1}{4}$xx3.14xx(10)^2-$\frac{1}{2}$xx10xx10` = 78.5 - 50 = 28.5 cm2 Hence, the correct answer is option (c). [Solution diagram: 77485_solution_1.png]

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