A circus tent is cylindrical to a height of 4 m and conical above it. If its diameter is 105 m and its slant height is 40 m, the total area of canvas required is

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KollegeApply · Accepted Answer

7920 m2 Total area of the canvas required = (Curved surface area of the cylinder) + (Curved surface area of the cone) = (2$\pi$rh + $\pi$rl) `= (2xx22/7xx105/2xx4)+($\frac{22}{7}$xx105xx40) ["d" = 105 "cm" r = $\frac{105}{2}$ "cm"] =(1320 + 6600) m2` = 7920 m2

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