A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 16 seconds would be roughly

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1020 Explanation - Current, i = 1A Time, t = 16s "i" = "q"/"t" "q" = "i" xx "t" q = 1 $\times$ 16 q = 16 C Now, q = n $\times$ e where, n is number of electrons lost or gained e = charge on 1 electron (1.6 $\times$ 10-19 C) "n" = "q"/"e" n = 16/(1.6 xx 10^(-19)) n = 1020

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