A cylindrical tube, open at both ends, has a fundamental frequency v. The tube is dipped vertically in water so that half of its length is inside the water. The new fundamental frequency is

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υ If v is the velocity of the wave and L is the length of the pipe, then the fundamental frequency for an open organ pipe is \nu = v/2L For a closed organ pipe of length L' = L/2, the fundamental frequency is \nu = v/4L' = v $\times$ $\frac{2}{4}$ $\times$ L = v/2L = v (When the pipe is dipped in water, it behaves like a closed organ pipe that is half the length)

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