A heavy stone is thrown from a cliff of height h with a speed v. The stoen will hit the ground with maximum speed if it is thrown

Question

KollegeApply · Accepted Answer

the speed does not depend on the initial direction. As the stone falls under the gravitational force, which is a conservative force, the total energy of the stone remains the same at every point during its motion. From the conservation of energy, we have: Initial energy of the stone = final energy of the stone i . e . , (K . E . )_i + (P . E . )_i = (K . E . )_f + (P . E . )_f \Rightarrow $\frac{1}{2}$m v^2 + mgh = $\frac{1}{2}$m( v_{\text{max}} )^2 \Rightarrow v_{\text{max}} = \sqrt{v^2 + 2\text{gh}} From the above expression, we can say that the maximum speed with which stone hits the ground does not depend on the initial direction.

AChoose Your Answer