A ladder 15 m long just reaches the top of a vertical wall. If the ladder makes an angle of $60^\circ$ with the wall, then the height of the wall is

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KollegeApply · Accepted Answer

Suppose AB is the wall and AC is the ladder. It is given that, AC = 15 m and \angleCAB = $60^\circ$. In right ∆ABC, \cos$60^\circ$= AB/AC \Rightarrow $\frac{1}{2}$ = AB/15 \Rightarrow AB = $\frac{15}{2}$ m Thus, the height of the wall is $\frac{15}{2}$ [Solution diagram: 63593_solution_1.png]

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