A light wave is incident normally on a glass slab of refractive index 1.5. If 10% of light gets reflected and the amplitude of the electric field of the incident light is 30 V/m, then the amplitude of the electric field for the wave propagating in the glass medium will be:

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KollegeApply · Accepted Answer

bb(24 V/m) Explanation: Percentage of refracted light: P_"refracted" = $\frac{96}{100}$ P_I Thus, n_2A_t^2 = $\frac{96}{100}$ n_1A_i^2 Here n1 = 1, n2 = 1.5 = $\frac{3}{2}$ Or `A_t^2 = $\frac{96}{100}$ xx $\frac{2}{3}$ xx (30)^2 = $\frac{192}{300}$ xx 900 = 0.64 $\times$ 900 = 576 = sqrt576` At = 24

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