A metallic cylinder of radius 8 cm and height 2 cm is melted and converted into a right circular cone of height 6 cm. The radius of the base of this cone is

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8 cm Radius of the cylinder = 8 cm Height of the cylinder = 2 cm Height of the cone = 6 cm Volume of the cylinder = Volume of the cone Therefore, `pixx8xx8xx2xx=$\frac{1}{3}$pixx"r"^2xx6 =>128 = "r"^2xx2 => "r"^2 = $\frac{128}{2}$ => "r"^2 = $\frac{128}{2}$ => "r"^2 = 64 => "r" = 8 "cm"` Hence, the radius of the base of the cone is 8 cm.

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