A parallelopiped is formed by planes drawn through the points (2, 3, 5) and (5, 9, 7), parallel to the coordinate planes. The length of a diagonal of the parallelopiped is

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7 \text{ The given points } \left( 2, 3, 5 \right) \text{ and } \left( 5, 9, 7 \right) \text{ are two diagonally opposite vertices of the parallelopiped as all of their coordinates are different }. \therefore \text{ Edges of the parallelopiped } = \left| 2 - 5 \right|, \left| 3 - 9 \right| \text{ and } \left| 5 - 7 \right| = 3, 6 \text{ and } 2 \text { Now} , \text{ Length of the diagonal of the parallelopiped } = \sqrt{\left( 3 \right)^2 + \left( 6 \right)^2 + \left( 2 \right)^2} \hspace{0.167em} \hspace{0.167em} \hspace{0.167em} \hspace{0.167em} \hspace{0.167em} \hspace{0.167em} = $\sqrt$(9 + 36 + 4) \hspace{0.167em} \hspace{0.167em} \hspace{0.167em} \hspace{0.167em} \hspace{0.167em} \hspace{0.167em} = $\sqrt$(49) \hspace{0.167em} \hspace{0.167em} \hspace{0.167em} \hspace{0.167em} = 7 \text{ Hence, length of the diagonal of the parallelopiped formed by the planes parallel to coordinate planes and drawn through points } \left( 2, 3, 5 \right) \text { and } \left( 5, 9, 7 \right) \text{ is 7 units } .

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