A particle is kept fixed on a turntable rotating uniformly. As seen from the ground the particle goes in a circle, its speed is 20 cm/s and acceleration is 20 cm/s2. The particle is now shifted to a new position to make the radius half of the original value. The new value of the speed and acceleration will be

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(a) 10 cm/s, 10 cm/s2 It is given that the turntable is rotating with uniform angular velocity. Let the velocity be \omega . We have: 	ext{v = r}\omega \Rightarrow 	ext{v} \propto 	ext{r} (	ext{P for constant }\omega) v/v' = r/r' \Rightarrow 	ext{v}' = \frac{	ext{v}}{2} = 10 	ext{ cm/s} Similarly, we have: a' = a/2 = 10	ext{ cm/ s}^2

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