A proton and an electron are placed in a uniform electric field.

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KollegeApply · Accepted Answer

The magnitudes of the forces will be equal. We know: \vec{F} = q \vec{E} For an electron and a proton, the value of q will be same, but the sign will be opposite. Hence, they will experience a force that will be equal in magnitude but opposite in direction. Now, \vec{F} = q \vec{E} = m \vec{a} \Rightarrow \vec{a} = \frac{q \vec{E}}{m} As the electron and proton have different values of mass m, they will have different magnitudes of acceleration. Also, they will differ in direction due to the opposite signs of q.

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