A TV transmission tower has a height of 240 m. Signals broadcast from this tower will be received by LOS communication at a distance of (assume the radius of earth to be 6.4 $\times$ 106 m) a. 100 km b. 24 km c. 55 km d. 50 km

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b, c and d Explanation: Here, h = 240 m d = ? R = 6.4 $\times$ 106 m The maximum distance on earth from the transmitter up to which a signal can be received is d = sqrt(2Rh) = `sqrt(2 xx (6.4 xx 10^6 xx 240)) = 55.4 xx 10^3` m = 55.4 km Therefore, the range of 55.4 km covers the distance 24 km, 55 km and 50 km.

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