A uniform wire of resistance 50 Ω is cut into 5 equal parts. These parts are now connected in parallel. The equivalent resistance of the combination is ______________ .

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KollegeApply · Accepted Answer

2 Ω Resistance of a wire is directly proportional to its length. So, when we cut the wire into 5 equal parts, the resistance of each part will be 10 Ω. On connecting these wires in parallel, the net resistance will be 1/R = $\frac{1}{10}$ + $\frac{1}{10}$ + $\frac{1}{10}$ + $\frac{1}{10}$ + $\frac{1}{10}$ \Rightarrow R = 2 \Omega

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