Air is pushed into a soap bubble of radius r to double its radius. If the surface tension of the soap solution in S, the work done in the process is

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KollegeApply · Accepted Answer

\text{ No . of surfaces of a soap bubble } = 2 \text{ Increase in surface area }= 4$\pi$(2r )^2 - 4$\pi$(r )^2 = 12 $\pi$ r^2 \text{ Total increase in surface area }= 2 $\times$ 12 $\pi$ r^2 = 24 $\pi$ r^2 \text{ Work done = change in surface energy } = S $\times$ 24 $\pi$ r^2 = 24 $\pi$ r^2 S

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