An electric dipole of dipole moment 2 $\times$ 10-8 C-m in a uniform electric field experiences a maximum torque of 6 $\times$ 10-4 N-m. The magnitude of the electric field is ______.

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An electric dipole of dipole moment 2 $\times$ 10-8 C-m in a uniform electric field experiences a maximum torque of 6 $\times$ 10-4 N-m. The magnitude of the electric field is 3.0 $\times$ 104 Vm-1. Explanation: Given: Electric dipole moment, p = 2 xx 10^-8 N/C Maximum torque, tau = 6 xx 10^-4 N-m $\theta$ = $90^\circ$ Electric field, E = ? The torque acting on the dipole: τ = pE sin$\theta$ $\Rightarrow$ 6 xx 10^-4 = 2 xx 10^-8 xx E $\Rightarrow$ E = 3 xx 10^4 Vm-1

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