An electric dipole of length 2 cm is placed at an angle of $30^\circ$ with an electric field 2 $\times$ 105 N/C. If the dipole experiences a torque of 8 $\times$ 10-3 Nm, the magnitude of either charge of the dipole is ______.

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An electric dipole of length 2 cm is placed at an angle of $30^\circ$ with an electric field 2 $\times$ 105 N/C. If the dipole experiences a torque of 8 $\times$ 10-3 Nm, the magnitude of either charge of the dipole is 4 µC. Explanation: Given: $\theta$ = $30^\circ$, E = 2 $\times$ 105 N/C, τ = 8 $\times$ 10-3 Nm and 2a = 2 cm = 0.02 m To find: Charge q = ? We know that, τ = pE sin$\theta$ = (q $\times$ 2a) E sin$\theta$ ....(∵ p = q $\times$ 20) q = tau/(2a.E sintheta) `q = (8 xx 10^-3)/(0.02 xx 2 xx 10^5 xx sin30^circ) = 400 xx 10^-3 xx 10^-5` q = 4 µC

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