An electron of energy 150 eV has wavelength of 10-10m. The wavelength of a 0.60 keV electron is?

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KollegeApply · Accepted Answer

0.50 Å λ = h/sqrt(meV) λ_1 $\alpha$ 1/sqrt(v_1) λ_2 $\alpha$ 1/sqrt(v_2) λ_1 / λ_2 = sqrt(v_2/v_1) `10^-10/λ_2 = sqrt(0.60xx10^3)/150 = sqrt($\frac{600}{150}$) = 2 10^-10/λ_2 = 10^-$\frac{10}{2}$ = 0.5 xx 10^-10m λ_2 = 0.5À`

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