Area of the region bounded by the curve y = cosx between x = 0 and x = $\pi$ is ______.

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KollegeApply · Accepted Answer

Area of the region bounded by the curve y = cosx between x = 0 and x = $\pi$ is 2 sq.units. Explanation: Given that: y = cos x, x = 0, x = $\pi$ Required area = `int_0^(pi/2) cos x "d"x + |int_(pi/2)^pi cos x "d"x| = [sin x]_0^(pi/2) + |(sin x)_(pi/2)^pi| = [sin pi/2 - sin 0] + |[sin pi - sin pi/2]| = (1 - 0) + |0 - 1|` = 1 + 1 = 2 sq.units [Solution diagram: 251731_solution_1.png]

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