Choose the correct alternative : The corner points of the feasible region are (0, 0), (2, 0), ($\frac{12}{7}$, $\frac{3}{7}$) and (0,1) then the point of maximum z = 7x + y

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Z = 7x + y At (0, 0), Z = 0 + 0 = 0 At (2, 0), Z = 7 (2) + 0 = 14 At `($\frac{12}{7}$, $\frac{3}{7}$), "Z" = 7($\frac{12}{7}$) + (3)/(7) = (87)/(7)` = 12.428 At (0, 1), Z = 0 + 1 = 1. The maximum value of Z is 14 and it occurs at (2, 0).

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