Choose the correct answer from the given four options : If the equation 2$x^{2}$ – 6x + p = 0 has real and different roots, then the values of p are given by

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KollegeApply · Accepted Answer

2$x^{2}$ – 6x + p = 0 Here, a = 2, b = –6, c = p b2 – 4ac = (–6)2 – 4 x 2 x p = 36 – 8p ∵ Roots are real and unequal. $\therefore$ b2 – 4ac > 0 $\Rightarrow$ 36 – 8p > 0 $\Rightarrow$ 36 > 8p $\Rightarrow$ (36)/(8) > p $\Rightarrow$ p < (36)/(8) $\Rightarrow$ p < (9)/(2).

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