Choose the correct option from the given alternatives: The mean and the variance of a binomial distribution are 4 and 2 respectively. Then the probability of 2 successes is

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KollegeApply · Accepted Answer

$\frac{28}{256}$ Explanation: np = 4, npq = 2 $\therefore$ q = $\frac{1}{2}$ and p = $\frac{1}{2}$ $\therefore$ "n"($\frac{1}{2}$) = 4 $\therefore$ n = 8 $\therefore$ P(X = 2) = `"^8C_2 ($\frac{1}{2}$)^8 = (8 xx 7)/(1 xx 2) xx $\frac{1}{256}$ = $\frac{28}{256}$`

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