Choose the correct option from the given alternatives : If the function f(x) = ax3 + bx2 + 11x – 6 satisfies conditions of Rolle's theoreem in [1, 3] and f'(2 + 1/sqrt(3)) = 0, then values of a and b are respectively

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1, – 6 [Hint : f(x) = ax3 + bx2 + 11x – 6 satisfies the conditions of Rolle's theorem in [1, 3] ∴ f(1) = f(3) ∴ a(1)3 + b(1)2 + 11(1) – 6 = a3 + b(3)2 + 11(3) - 6 ∴ a + b + 11 = 27a + 9b + 33 ∴ 26a + 8b = – 22 ∴ 13a + 4b = – 11 Only a = 1, b = – 6 satisfy this equation].

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