Consider the following frequency distribution: Class 0 – 5 6 – 11 12 – 17 18 – 23 24 – 29 Frequency 13 10 15 8 11 The upper limit of the median class is:

Question

KollegeApply · Accepted Answer

17.5 Explanation: According to the question, Classes are not continuous, Hence, we make the data continuous by subtracting 0.5 from lower limit and adding 0.5 to upper limit of each class. Class Frequency Cumulative Frequency 0.5 – 5.5 13 13 6.5 – 11.5 10 23 11.5 – 17.5 15 38 17.5 – 23.5 8 46 23.5 – 29.5 11 57 According to the question, N/2 = $\frac{57}{2}$ = 28.5 28.5 lies in between the interval 11.5 – 17.5. Therefore, the upper limit is 17.5

AChoose Your Answer