ΔАВС ~ ΔDEF such that AB = 9.1 cm and DE = 6.5 cm. If the perimeter of ΔDEF is 25 cm, what is the perimeter of ΔАВС?

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KollegeApply · Accepted Answer

35 cm Explanation: Similar triangles have all corresponding lengths in the same ratio, so the scale factor k = (AB)/(DE) = (9.1)/(6.5) = $\frac{91}{65}$ = $\frac{7}{5}$ Perimeters scale by the same factor, so perimeter (ABC) = 25 $\times$ $\frac{7}{5}$ = 35 cm

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