f the coordinates of one end of a diameter of a circle are (2, 3) and the coordinates of its centre are (−2, 5), then the coordinates of the other end of the diameter are

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Let O(−2, 5) be the centre of the given circle and A(2, 3) and B(x, y) be the end points of a diameter of the circle. Then, O is the mid-point of AB. Using mid-point formula, we have 	herefore 2 + x/2 = - 2 and 3 + y/2 = 5 \Rightarrow 2 + x = - 4 and 3 + y = 10 \Rightarrow x = - 6 and y = 7 Thus, the coordinates of the other end of the diameter are (−6, 7). Hence, the correct answer is option A. [Solution diagram: 64150_solution_1.png]

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