Find the perimeter of a sector of a circle if its measure is $90^\circ$ and radius is 7 cm.

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KollegeApply · Accepted Answer

25 cm Explanation: Here, r = 7 cm and $\theta$ = 90º $\therefore$ Perimeter of the sector = $\theta$/(360^circ) xx 2$\pi$r + 2r = `(90^circ)/(360^circ) xx 2 xx $\frac{22}{7}$ xx 7 + 2 xx 7` = 11 + 14 = 25 cm

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