Given a = 3 sec2 θ and b = 3 tan2 θ – 2. The value of (a – b) is ______.

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Given a = 3 sec2 $\theta$ and b = 3 tan2 $\theta$ – 2. The value of (a – b) is 5. Explanation: a – b = 3 sec2$\theta$ – (3 tan2$\theta$ – 2) = 3(sec2$\theta$ – tan2$\theta$) + 2 Using sec2$\theta$ – tan2$\theta$ = 1 gives 3 $\times$ 1 + 2 = 5.

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