i. Lines 2x + 3y = 5 and px + 6y = 1 are parallel then p = 1. ii. Equation of a line parallel to 2x + y = 4 and passing through (3, 5) is 2x + y = 2.

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Neither (i) nor (ii) Explanation: $\Rightarrow$ Going through (i) statement, For lines to be parallel, the ratio of their x and y coefficients must be equal: 2/p = $\frac{3}{6}$ 2/p = $\frac{1}{2}$ $\therefore$ p = 4 Since the statement says p = 1, it is invalid. $\Rightarrow$ Going through (ii) statement, A line parallel to 2x + y = 4 will have the same form: 2x + y = k, To find k, substitute the point (3, 5): 2(3) + 5 = k 6 + 5 = k $\therefore$ k = 11 The correct equation should be 2x + y = 11, not 2x + y = 2. So, this statement is also invalid.

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