If –2 and 3 are the zeros of the quadratic polynomial x2 + (a + 1)x + b then

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a = –2, b = –6 Explanation: $\alpha$ + $\beta$ = 3 + (–2) = 1 And $\alpha$$\beta$ = 3 $\times$ (–2) = –6 $\therefore$ –(a + 1) = 1 $\Rightarrow$ a + 1 = –1 $\Rightarrow$ a = –2 Also, b = –6

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