If 220 V potential difference is applied across an electric bulb, a current of 0.45 A flows in the bulb. What must be the power of the bulb?

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KollegeApply · Accepted Answer

99 W Explanation: Given: Potential difference = 220 V, Current = 0.45 A Power (W) = Potential difference (V) $\times$ Current (A) = 220 $\times$ 0.45 W = 99 W So, the bulb must be of power 99 W.

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