If A and B are square matrices of order 2, then det (A + B) = 0 is possible only when

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(d) A + B = O 	ext{ Let }A = \left[ a_{i j} ight]	ext{ and }B = \left[ b_{i j} ight]	ext{ be a square matrix of order 2 .} 	ext{ As their orders are same, A + B is defined as} A + B = \left[ a_{i j} + b_{i j} ight] \Rightarrow \left| A + B ight| = \left| a_{i j} + b_{i j} ight| Now, \left| A + B ight| = 0 \Rightarrow \left| a_{i j} + b_{i j} ight| = 0 \Rightarrow \left[ a_{i j} + b_{i j} ight] = 0 \left[	ext{ each corrsponding term is 0 }ight] \Rightarrow A + B = 0

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