If angles A, B, C to a ∆ABC from an increasing AP, then sin B =

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KollegeApply · Accepted Answer

Let the angles of a triangle Δ ABC be (a-d), (a),(a+d)espectively which constitute an A.P.As we know that sum of all the three angles of a triangle is $180^\circ$. so, (a-d)+a(a+d)=$180^\circ$ So, a =$60^\circ$ Therefore, $\angle$ B= $60^\circ$ Hence, sin $\angle$B= sqrt3/2

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