If chlorine gas is passed through hot and conc. aqueous sodium hydroxide solution, the products formed have chlorine in different oxidation states. These oxidation states are indicated as:

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−1 and +5 Explanation: When chlorine gas reacts with hot, concentrated NaOH, a disproportionation reaction occurs: \ce{3Cl2 + 6NaOH -> 5NaCl + NaClO3 + 3H2O} In NaCl, chlorine is in the −1 oxidation state. In NaClO3, chlorine is in the +5 oxidation state. Thus, the two oxidation states of chlorine in the products are −1 and +5.

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