If cosec θ = sqrt(10) then sec θ = ?

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KollegeApply · Accepted Answer

bb(sqrt(10)/3) Explanation: cosec $\theta$ = sqrt(10) $\Rightarrow$ `sin $\theta$ = 1/sqrt(10) = (BC)/(AC). Let BC = k and AC = sqrt(10)k`. AB2 = (AC2 – BC)2) = (10k2 – k2) = 9k2 $\therefore$ AB = sqrt(9k^2) = 3k $\therefore$ sec $\theta$ = (AC)/(AB) = (sqrt(10)k)/(3k) = sqrt(10)/3 [Solution diagram: 470304_solution_1.png]

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