If each edge of a cube is increased by 50%, the percentage increase in the surface area is

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KollegeApply · Accepted Answer

125% Let the original edge of the cube be a units. Then, the original surface area of the cube = 6a2 units New edge of the cube = 150% of a = (150"a")/100 = (3"a")/2 Hence, new surface area = 6 $\times$ ((3"a")/2)^2 =(27a^2)/2 Increase in area =((27a^2)/2 - 6"a"^2) =(15"a"^2)/2 % increasein surface area `= ("15a"^$\frac{2}{2}$xx1/(6"a"^2xx100))%` =125 %

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