If four times the sum of the areas of two circular faces of a cylinder of height 8 cm is equal to twice the curve surface area, then diameter of the cylinder is

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Let r be the radius of cylinder. Area of circular base of cylinder =pir^2 The height of cylinder h = 8 cm The C.S.A. of cylinder= 2pir xx 8 = 16 pir Clearly, `4 xx (pir^2 + pir^2) = 2 xx (pir) 8 pir^2 = 32 pi r 8r^2 = 32r` r = 4cm The diameter of cylinder d = 4 xx 2 = 8 "cm"

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