If $\pi$ is taken as $\frac{22}{7}$ the distance (in metres) covered by a wheel of diameter 35 cm, in one revolution, is

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Diameter of wheel (d) = 35 cm Radius of wheel (r) = "d"/2 = $\frac{35}{2}$ cm $\therefore$ The distance covered by the wheel in 1 revolution is equal to the circumference of the wheel = 2$\pi$r = 2 $\times$ $\frac{22}{7}$ $\times$ $\frac{35}{2}$ = `cancel2 $\times$ 22/(cancel(7)1) $\times$ (cancel(35)5)/cancel2` = 22 $\times$ 5 = 110 cm The distance covered by the wheel in one revolution (in m) is given by = $\frac{110}{100}$ = 1.1 m

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