If k + 6, 2k + 6 and 5k − 2 are in A.P., then the value of k is ______.

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If k + 6, 2k + 6 and 5k − 2 are in A.P., then the value of k is 4. Explanation: a = k + 6 b = 2k + 6 c = 5k − 2 2b = a + c 2(2k + 6) = (k + 6) + (5k − 2) 4k + 12 = 6k + 4 12 − 4 = 6k − 4k 8 = 2k k = $\frac{8}{2}$ k = 4

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