If sec 4A = cosec (A – $10^\circ$) and 4A is acute then A = ?

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KollegeApply · Accepted Answer

$20^\circ$ Explanation: sec 4A = cosec (A – $10^\circ$) $\Rightarrow$ cosec ($90^\circ$ – 4A) = cosec (A – $10^\circ$) $\Rightarrow$ $90^\circ$ – 4A = A – $10^\circ$ $\Rightarrow$ 5A = $100^\circ$ $\Rightarrow$ A = $20^\circ$

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