If tan $\theta$ = $\frac{8}{15}$ then cosec $\theta$ = ?

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KollegeApply · Accepted Answer

bb($\frac{17}{8}$) Explanation: tan $\theta$ = (BC)/(AB) = $\frac{8}{15}$. Let BC = 8k and AB = 15k. Then, AC2 = AB2 + BC2 = (225k2 + 64k2) = 289k2 $\therefore$ AC = sqrt(289k^2) = 17k $\therefore$ cosec $\theta$ = (AC)/(BC) = (17k)/(8k) = $\frac{17}{8}$ [Solution diagram: 470297_solution_1.png]

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