If tan $\theta$ = sqrt(3) then sec $\theta$ = ?

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KollegeApply · Accepted Answer

2 Explanation: tan $\theta$ = sqrt(3) $\Rightarrow$ (BC)/(AB) = sqrt(3)/1 Let BC = sqrt(3)k and AB = k. Then, AC2 = (AB2 + BC2) = (k2 + 3k2) = 4k2 $\Rightarrow$ AC = sqrt(4k^2) $\Rightarrow$ AC = 2k $\therefore$ sec $\theta$ = (AC)/(AB) = (2k)/k = 2 [Solution diagram: 470299_solution_1.png]

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