If the circumference of a circle increases from 4$\pi$ to 8$\pi$, then its area is

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Let the circumference C=4pi $\therefore$ 2pi r=4pi $\therefore$ r=2 Therefore, area of the circle when radius of the circle is 2 can be calculated as below, pir^2=$\frac{22}{7}$xx4 .........(1) Now when circumference isC=8pi, then the radius of the circle is calculated as below, $\therefore$ 2pi r=8pi $\therefore$ r=4 Therefore, area of the circle when radius of the circle is 2 can be calculated as below, pi r^2=$\frac{22}{7}$xx16 `$\therefore$ pi r^2=4($\frac{22}{7}$xx4)............(2)` Therefore, from equation (1) and (2) we can say that its area is quadrupled

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