If the difference between the circumference and radius of a circle is 37 cm, then its area is

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KollegeApply · Accepted Answer

We have given the difference between circumference and radius of the circle. Let C be the circumference, r be the radius and A be the area of the circle. Therefore, from the given condition we have C-r=2pir-r $\therefore$ 37=2pir-r $\therefore$37=r(2pi-1) $\therefore$ r=37/((2pi-1)) Now we will substitute pi=$\frac{22}{7}$ $\therefore$ r= 37/((2xx22/7-1)) $\therefore$ r=37/(($\frac{44}{7}$-1)) $\therefore$ r=37/(((44-7)/7)) $\therefore$ r=37/(($\frac{37}{7}$)) $\therefore$ r=37xx7/37 $\therefore$ r=7 Now we will substitute the value of r inA=pir^2. $\therefore$ A=pixx7^2 Now we will substitute pi=$\frac{22}{7}$ $\therefore$ A=$\frac{22}{7}$xx7^2 $\therefore$=22xx7 $\therefore$ A=154 Therefore, area of the circle is 154 cm^2

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