If the first term of an AP is –5 and the common difference is 2, then the sum of the first 6 terms is ______.

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If the first term of an AP is –5 and the common difference is 2, then the sum of the first 6 terms is 0. Explanation: Given, a = –5 And d = 2 $\therefore$ S6 = $\frac{6}{2}$[2a + (6 - 1)d] ...[∵ S_n = n/2[2a + (n - 1)d]] = 3[2(–5) + 5(2)] = 3(–10 + 10) = 0

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