If the intercept form of the equation of the plane 2x − 3y + 4z = 12 is x/a + y/b + z/c = 1, then the values of a, b, c are respectively,

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a = 6, b = −4, c = 3 Explanation: Given that, If the intercept form of the equation of the plane ax - by + cz = d is x/a + y/b + z/c = 1 we have, 2x − 3y + 4z = 12 On dividing by 12 on both side, `(2x)/12 − (3y)/12 + (4z)/12 = $\frac{12}{12}$ x/6 − y/4 + z/3 = 1` On comparing with the equation. (i) a = 6, b = − 4, c = 3 $\therefore$ Option a = 6, b = −4, c = 3 is correct.

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