If the length of diagonal of square is sqrt(2), then what is the length of each side?

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KollegeApply · Accepted Answer

1 Explanation: Let ABCD be the given square. In ∆ABC, $\angle$B = $90^\circ$ $\therefore$ AC2 = AB2 + BC2 ...[Pythagoras theorem] $\therefore$ (sqrt(2))^2 = AB^2 + AB^2 ...[Sides of the square] $\therefore$ 2 = 2AB2 $\therefore$ AB2 = 1 $\therefore$ AB = 1 unit

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