If the points P (x, y) is equidistant from A (5, 1) and B (−1, 5), then

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It is given that P (x , y) is equidistant to the point A (5,1) " and " B (-1 , 5) So, PA^2 = PB^2 So apply distance formula to get the co-ordinates of the unknown value as, `(x - 5)^2 + (y - 1)^2 = (x +1)^2 + (y-5)^2` On further simplification we get, 25-10x + 1 - 2y = 1 +2x + 25 - 10y So, 12x = 8y Thus, 3x = 2y

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