If the radii of the ends of a bucket are 5 cm and 15 cm and it is 24 cm high, then its surface area is

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KollegeApply · Accepted Answer

1711.3 cm2 Let R and r be the radii of the top and base of the bucket, respectively, and let h and l be its height and slant height. Then, R = 15 cm , r = 5 cm , h = cm `"l"=sqrt("h"^2 + ("R" - r)^2) =sqrt((24)^2 + (15 - 5)^2) =sqrt(576+100) =sqrt(676) = 26 cm surface area of the bucket = pi["r"^2 + l ("R" + "r")] = 3.14xx(5^2 + 26(15+5)) = (3.14xx(26xx20+25)) "cm"^2 = 1711.3 "cm"^2

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